Find g''(x) if g(x) = 6x^3-4x^2 +8x -3

Given the function g(x) = 6x^3 - 4x^2 + 8x
-3

We need to find the second derivative
g''(x).

First we will differentitae
g(x).

==> g'(x) = (6x^3)' - (4x^2)' + (8x)'
-(3)'

                  = 18x^2 - 8x + 8 -
0

==> g'(x) = 18x^2 - 8x
+8

Now we will differentiate
again:

==> g''(x) = (18x^2)' -(8x)' +
(8)'

                 = 36x - 8 +
0

==> g''(x) = 36x
-8