If y=(1+x^2)^3 find dy/dx.

y = (1+x^2)^3.

We have to
find dy/dx

We  use d/dx {u(v(x))} =  (du/dv)
(dv/dx)

Let v(x) = 1+x^2

d/dx
{v(x)} = d/ dx {1+x^2} = d/dx(1)+ d/ dx(x^2) = =
0+2x

Therefore d/dx{1+x^2)^3 = 3(1+x^2^(3-1)*d/dx
(1+x^2)

d/dx(1+x^2)^3 =
3(1+x^2)^2*2x

Therefore dy/dx =
 d/dx(1+x^2)^3 = 6x(1+x^2)^2.