How do I solve the following equation : 4(2y+1)=2(12-y)I know the answer is y=2 but i do not know how to work it out

You have to solve the equation 4(2y+1) =
2(12-y).

First let's start with 4(2y+1) =
2(12-y)

open the
brackets

=> 4*2y + 4*1 = 2*12 -
2*y

=> 8y + 4 = 24 -
2y

now move the terms with y to one side, and the numeric
terms to the other side. Remember that when you move a term to the other side of the
equation, its sign changes

=> 8y + 2y = 24 -
4

=> 10y = 20

divide
both the sides by 10

=> y = 20/10 =
2.

That's how you get y = 2. Hope it's clear
now.