A plane is defined by the equation: x - 7y - 18z = 0. Write the coordinates of 3 points on this plane.

Let z = 1/2. Then x-7y -18*(1/2) = 0. So x-7y = 9 , when
z= 0.5.

Therefore x= 2, y = -1  and z = 1/2 is on x-7y-18z
as 7-(-2)-18*(1/2) = 0. So (2, -1, 1/2) is on the
plane.

Let  z = 1,  then x-7y = 18. So  x= 4, 7 = -2 
satisfies x-7y = 18, as 4 -7*-2   = 18. So  ( 4,-2, 1) is
on the plane x-7y -18z = 0.

Let x = 11 , y = -1, then x-7y
-18z = 0, for  11-7*-1 = 18z. Or 18z = 18. Or z = 1. So (11, -1 ,
1) is on the plane x-7y-18z.

So the 3 points
on  the plane x-7y-18z = 0
are

(2, -1, 1/2) , (4, -2, 1)
, (11, -1, 1).