To evaluate the integral, we'll change the
variable:
1 + x^3 = t
We'll
differentiate both sides:
3x^2dx =
dt
x^2dx = dt/3
We'll re-write
the integral in t:
Int x^2(x^3+1)^4 dx = Int t^4
dt/3
Int t^4 dt/3 = (1/3)Int t^4
dt
(1/3)Int t^4 dt = (1/3)*(t^5/5)
+C
(1/3)Int t^4 dt = t^5/15 +
C
Int x^2(x^3+1)^4 dx = (x^3+1)^5/15 +
C
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