Wednesday, January 28, 2015

Evaluate the indefinite integral of y=x^2(x^3+1)^4.

To evaluate the integral, we'll change the
variable:


1 + x^3 = t


We'll
differentiate both sides:


3x^2dx =
dt


x^2dx = dt/3


We'll re-write
the integral in t:


Int x^2(x^3+1)^4 dx = Int t^4
dt/3


 Int t^4 dt/3 = (1/3)Int  t^4
dt


(1/3)Int  t^4 dt = (1/3)*(t^5/5)
+C


(1/3)Int  t^4 dt = t^5/15 +
C


Int x^2(x^3+1)^4 dx = (x^3+1)^5/15 +
C

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