Find the distance between the line 3x+4y=11 and the point (2,5).

We are given the coordinates of the point as ( 2 , 5) and
the equation of the line is 3x + 4y = 11 or 3x + 4y - 11 =
0.

Now the relation for calculating the distance d of a
point (x1, y1) from the line ax+by +c = 0, is:

d =
|ax1+by1+c|/ sqrt (a^2+b^2)

Substituting the values we
have

d = | 3*2 + 5* 4 - 11| / sqrt ( 3^2 +
4^2)

=> d = | 6 + 20 -11| / sqrt
25

=> d = 15 /
5

=> d =
3

Therefore the required distance is
3.