Monday, November 12, 2012

What are the real solution of equation? 2x^2+6x+11=6 ?

First, we'll move all terms to the left
side:


2x^2 + 6x + 11 - 6 =
0


We'll combine like
terms:


2x^2 + 6x + 5 = 0


Now,
we'll verify if the equation has real solutions. For this reason, we'll calculate the
discriminant of the equation.


delta = b^2 - 4ac, where
ab,c, are the coefficients of the equation:


ax^2 + bx + c =
0


We'll identify a,b,c:


a =
2


b = 6


c =
5


delta = 36 - 40 = -4 <
0


Since delta is negative, then the equation
has no real roots, but it has complex roots.

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