We'll calculate the first ratio:
cosB/sinC
We know that A = pi/2 and the sum of the angles
of a triangle is pi.
A + B + C =
PI
pi/2 + B + C = pi
B + C =
pi - pi/2
B +C = pi/2
B =
pi/2 - C
Now, we'll apply cosine function both
sideS:
cos B = cos (pi/2 -
C)
cos B = cos pi/2*cos C + sin pi/2*sin
C
cos pi/2 = 0 and sin pi/2
=1
cos B = sin C
cosB/sinC =
sin C/sin C = 1
Now, we'll calculate the second
ratio:
cosC/sinB = cos (pi/2 - B)/sin
B
cosC/sinB = sin B/sin
B
cosC/sinB = 1
The value of
the given expression is:
E = 1 +
1
E =
2
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