Thursday, July 19, 2012

Find all the zeros of the function f(x)=x^2-8x-9

We have to find the zeros of the function f(x) = x^2 - 8x
- 9


For this we equate f(x) to 0 and solve the quadratic
equation that is obtained.


f(x) =
0


=> x^2 - 8x - 9 =
0


=> x^2 - 9x + x - 9 =
0


=> x(x - 9) +1(x - 9) =
0


=> (x - 9)(x + 1) =
0


for x - 9 = 0 , we have x =
9


for x + 1 = 0, we have x =
-1


The requires zeros are x = -1 and x =
9

No comments:

Post a Comment

Calculate tan(x-y), if sin x=1/2 and sin y=1/3. 0

We'll write the formula of the tangent of difference of 2 angles. tan (x-y) = (tan x - tan y)/(1 + tan x*tan y) ...