We have to find the zeros of the function f(x) = x^2 - 8x
- 9
For this we equate f(x) to 0 and solve the quadratic
equation that is obtained.
f(x) =
0
=> x^2 - 8x - 9 =
0
=> x^2 - 9x + x - 9 =
0
=> x(x - 9) +1(x - 9) =
0
=> (x - 9)(x + 1) =
0
for x - 9 = 0 , we have x =
9
for x + 1 = 0, we have x =
-1
The requires zeros are x = -1 and x =
9
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