The right angled triangle ABC has AB=6, BC=8 and AC is the hypotenuse. Find sinA, cosA and tanA.

Given the the right angle triangle ABC such that AC is the
hypotenuse.

Then, the right angle is
B.

==> Given the legs
are:

AB = 6

BC =
8

Then, we will calculate the hypotenuse AC using the
formula.

==> AC^2 = BC^2 +
AB^2

==> AC^2 = 6^2 + 8^2 = 36+64 =
100

==> AC = 10

Now we
need to find the following:

sinA = opposite/
hypotenuse.

We know that the side that is opposite to the
angle A is BC

==> sinA = BC/AC = 8/10 =
4/5

==> cosA = adjacent/
hypotenuse

                 = AB/AC = 6/10 =
3/5

==> tanA = sinA/cosA =
4/3

==> sinA = 0.8

==>cosA =
0.6

==> tanA =
4/3