cosx=1-sinx
sinx =
1-cosx
devide the equation by
cosx
tan = secx -1
tanx = secx
- 1
we know that tan2x =
2tanx/(1-tan²x)
tan2x = 2(secx-1)/[1-
(secx-1)²]
tan2x = 2(secx-1)/[1
-(sec²x-2secx+1)]
tan2x = 2(secx-1)/[1
-sec²x+2secx-1)]
tan2x =
2(secx-1)/[2secx-sec²x]
tan2x =
2(secx-1)/secx(2-secx)
tan2x =
2(1-cosx)/cosx.secx(2-secx)
tan2x =
2(1-cosx)/(2-secx)
tan2x =
2cos(1-cosx)/(2cosx-1)
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