We know that any periodic motion is a simple harmonic
motion (SHM) and could be written as x(t) = A sin (wt+p), where A is the amplitude , w
is the angular velocity, p is the phase difference and t is the time in
minutes.
Since the vertical maximum distance between the
highest and lowest points in the motion of the boat is 9 m, the amplitude A = 9/2 = 4.5
m
So here, A = 9/2, w = 2pi/ 5 radians per
minute.
So at the time t = 0, the equation of motion given
by : -4.5 = 4.5 sin {5t+p}. So sin (5*0+p) =
-1.
=> 5t+p = -pi/2, or p =
-pi/2.
Therefore the required model of the motion is x(t) =
4.5 sin(5t-pi/2) in terms of sin function.
To write the
equation in terms of Cosine function:
Since cos x = sin
(pi/2 - x), we can rewrite the above equation as
below:
x(t) = 4.5 cos {pi/2 - (
5t-pi/2)}.
=> x(t) = 4.5 cos {-5wt +
pi}.
=> x(t) = 4.5 cos (5wt- pi) , as cos (-x) =
cosx.
Therefore the required equation of the simple
harmonic motion of the boat is given by:
x(t) = 4.5
(5wt-pi). Or x (t) = cos (5t+pi) , as x(t) = x(t+2pi) for any
SHM.
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