We will calculate the distance between the first car and
the starting point.
Let the car begins at A and move
perpendicularly to B.
The speed if 40
km/h
Then the distance after 2 hours is : D = Speed * Time
= 40*2 = 80 km
Then the distance between A and B is
80.
Now we will assume that the other car is at
C.
We know that the length of AC is the initial distance
between the cars which is 10 km
==> Then AC =
10.
Now we have a right angle triangle ABC such
that:
AB = 80
AC =
10
We nee to find the distance between both cars after 2
hours which is the length of the line BC.
==> BC^2 =
AB^2 + AC^2 = 10^2 + 80^2 = 6500
==> BC = sqrt6500 =
80.62 km ( approx.)
Then the distance between
the cars after 2 hours is 80.62 km.
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