Give the zeros of polynomial P and list their multiplicities : P(x) = -x(- x - 2)^2(x + 2).

The function P(x) =  -x(- x - 2)^2(x + 2)is not
polynomial, as (-x-2)^2(x+2) is exponential.

To find the
zeros of P(x) = -x(- x - 2)^2(x + 2).

The zeros of P(x) are
those values of x  for which P(x) = 0.

=> the values
of x for which  -x(- x - 2)^2(x + 2) = 0.

=>
(-x)*(-x-2)^2(x+2) = 0.

=> -x = 0, or (-x-2)^2(x+2)
= 0.

(-x-2)^2(x+2) = 0 gives: (x+2)^2(x+2) * (-1)^2x =
0.

=> (x+2)^2(x+2) =
0.

=> y^2y = 0. There is no number for which y^2y
=0, as 0^0 is undefined.

Therefore x = 0 is
the only zero of P(x).