Find the values of "a" for the line y= ax - 8 if it intercepts the x axis at the point where x=2.

y = ax-8 intersects  x axis at x =
2.

We know the equation of x axis is y =
0.

Therefore y= ax-8 ...(1) and y = 0...(2) are the two
lines whose intersection is x=2, and y= 0. Or at (x,y) =
(2,0).

So we put y = 0 in (1) and
get:

0 = ax-8.

Therefore ax=
8, or a = 8/x. but x = 2,

So a = 8/2 =
4.

Therefore  the value of a = 4 in order that y = ax-8 and
y = 0 intersect at x = 2.