Evaluate the integral of 3/(x^1/2)

We'll write the indefinite
integral:

Int 3dx/sqrt x = 3Int dx/sqrt
x

We'll multiply both, denominator and numerator, by
2:

 2/2sqrtx = 2*(1/2sqrt x) =
2*(sqrtx)'

3Int dx/sqrt x = 3Int
2*(sqrtx)'dx

3Int 2*(sqrtx)'dx = 3*2Int
(sqrtx)'dx

3*2Int (sqrtx)'dx = 6 sqrt x +
C

Int 3dx/sqrt x = 6 sqrt x +
C