Find the x intercepts of the graph of y = -x^2 + 3x + 18

y= -x^2 + 3x + 18

We need to
find the x-intercept of the curve y.

The x-intercept is the
point where the curve y meets the x-axis.

Then the values
of y would be zero.

==> -x^2 + 3x + 18 =
0

==> We will factor
-1.

==> -(x^2 -3x -18) =
0

Now we will
factor.

==> -(x-6)(x+3) =
0

==> x = 6  , -3

There
are 2 values for x. Then, the curve y meets the x-axis at two points ( 6,0) and
(-3,0)

Then x-intercepts are (6,0) and
(-3,0)