If (x+1),3x,(4x+2) are consecutive terms of an A.P, then what is the value of x?

We are given that (x+1), 3x, (4x+2) are in A.P. As they
are A.P., consecutive terms have a common difference.

So 4x
+ 2 - 3x = 3x - x - 1

=> 4x - 3x + 2 = 2x -
1

=> x + 2 = 2x -
1

=> 2x - x = 2 +
1

=> x =
3

Therefore if x = 3, (x+1), 3x, (4x+2) are
in A.P